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3x 2 5xy 2y 2 x 9y 4

3x^2+5xy-2y^2+x+9y-4=3x^2+(5y+1)x-(2y^2-9y+4)=3x^2+(5y+1)x-(y-4)(2y-1)=(3x-y+4)(x+2y-1)十字交叉

答案如下:

原式=(3x-y)(x+2y)+x+9y-4 =(3x-y)(x+2y)-(3x-y)+4x+8y-4 =(3x-y)(x+2y-1)+4(x+2y-1) =(3x-y+4)(x+2y-1)

3x²+5xy-2y²+x+9y-4 =3x²+5xy-2y²+4x-3x+8y+y-4 =(x+2y)(3x-y)+4x+8y-3x+y-4 =(x+2y)(3x-y)+4(x+2y)-(3x-y+4) =(x+2y)(3x-y+4)-(3x-y+4) =(x+2y-1)(3x-y+4) 2x²+xy-y²-4x+5y...

12ab-6(a^2+b^2)=-6(a^2-2ab+b^2)=-6(a-b)^2 3x^2+5xy-2y^2+x+9y-4=(3x-y)(x+2y)+x+9y-4=(3x-y+4)(x+2y-1)

(ax+by+c)(mx+ny+p)类型的。先配二次项,(3x-y)(x+2y),再配x,(3x+4)(x-1)。合到一块检查y,答案是(3x-y+4)(x+2y-1)

用双十字相乘法分解因式: 3x²+5xy-2y²+x+9y-4 =(3X-Y+4)(X+2Y-1)。

令t=x+1/x,则x²+1/x²=t²-2,原式:2(t²-2)-3t-1=0 即2t²-3t-5=0,解得t=3或者-1/2 即x+1/x=3或x+1/x=-1/2 而x+1/x=5/2,化简得2x²-5x+2=0 即(x-2)(2x-1)=0,解得x=2或1/2 x+1/x=-1化简得x²+x+1=0无解 综上:x=2...

3x²+5xy-2y²+x+9y+m =(3x+2y)(3x-y)+(28/9)(3x+2y)-(25/9)(3x-y)+m =(3x+2y)(3x-y+ 28/9) -(25/9)(3x-y +28/9) +m+700/81 =(3x-y+ 28/9)(3x+2y -25/9) +m+700/81 要多项式分解成两个关于x、y的二元一次三项式的积,m+700/81=0 m=-700/...

x,y满足:|x-1|+(y+2)二次方=0 那么x-1=0,y+2=0 所以x=1,y=-2 所以2x^2y-(5xy^2-4(xy^2-4分之3x二次方y)+x二次方y)+3xy二次方 =2x^2y-(5xy^2-4xy^2+3x^2y+x^2y)+3xy^2 =2x^2y-5xy^2+4xy^2-3x^2y-x^2y+3xy^2 =-2x^2y+2xy^2 =2xy(-x+y) =2*...

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